Returns an Integer indicating the subtype of a variable.
Syntax
VarType(varname)
The required varname argument is a Variant containing any variable except a variable of a user-defined type.
Return Values
| Constant | Value | Description |
|---|---|---|
| vbEmpty | 0 | Empty (uninitialized) |
| vbNull | 1 | Null (no valid data) |
| vbInteger | 2 | Integer |
| vbLong | 3 | Long integer |
| vbSingle | 4 | Single-precision floating-point number |
| vbDouble | 5 | Double-precision floating-point number |
| vbCurrency | 6 | Currency value |
| vbDate | 7 | Date value |
| vbString | 8 | String |
| vbObject | 9 | Object |
| vbError | 10 | Error value |
| vbBoolean | 11 | Boolean value |
| vbVariant | 12 | Variant (used only with arrays of variants) |
| vbDataObject | 13 | A data access object |
| vbDecimal | 14 | Decimal value |
| vbByte | 17 | Byte value |
| vbUserDefinedType | 36 | Variants that contain user-defined types |
| vbArray | 8192 | Array |
Note These constants are specified by Visual Basic for Applications. The names can be used anywhere in your code in place of the actual values.
Remarks
The VarType function never returns the value for vbArray by itself. It is always added to some other value to indicate an array of a particular type. The constant vbVariant is only returned in conjunction with vbArray to indicate that the argument to the VarType function is an array of type Variant. For example, the value returned for an array of integers is calculated as vbInteger + vbArray, or 8194. If an object has a default property, VarType (object) returns the type of the object's default property.